Pq and rs are two lines that intersect at point t.

which fact is used to prove that angle pts is always equal to angle rtq?

the sum of the measures of angles rtq and qts is equal to the sum of the measures of angles
qts and pts.

angle rtq and angle qts are complementary angles.

the sum of the measures of angles rtq and pts is equal to the sum of the measures of angles rtp and qts.

angle rtq and angle pts are supplementary angles.

A.

Step-by-step explanation:

We are given that two lines PQ and RS are intersect at point T.

We have to find the fact which is used to prove that angle PTS is always equal to angle RTQ.

We know that linear angles are supplementary and sum is 180 degrees

Therefore,

From both equation we get

Cancel angle QTS on both sided the we get

Hence, option A is true.

Therefore, when two lines are intersect then opposite angles are equal.

answer is 67%

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.