The head of maintenance at xyz rent-a-car believes that the mean number of miles between services is 21352135 miles, with a variance of 145,924145,924. if he is correct, what is the probability that the mean of a sample of 4040 cars would differ from the population mean by less than 2929 miles? round your answer to four decimal places.

i think the answer is b)

step-by-step explanation:

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2