The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0.1 mm. a random sample of 200 wafers is drawn. what is the probability that the sample mean warpage exceeds 1.305 mm?

0.2389

Step-by-step explanation:

The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0.1 mm.

A random sample of 200 wafers is drawn

we are supposed to find What is the probability that the sample mean warpage exceeds 1.305 mm

We will use central limit theorem

According to central limit theorem:

Now we are supposed to find  What is the probability that the sample mean warpage exceeds 1.305 mm i.e.P(x>1.305)

Refer the z table

P(z<0.71)=0.7611

Hence the probability that the sample mean warpage exceeds 1.305 mm is 0.2389

good luck on your studies! : )

david edward.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)