Mathematics, 15.11.2019 19:31 bicaplinger7766
Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus startfraction 1 over 8 endfraction right-parenthesis minus startfraction 3 over 5 endfraction x equals startfraction 55 over 4 endfraction x = 2 left-parenthesis x minus startfraction 1 over 8 endfraction right-parenthesis minus startfraction 3 over 5 endfraction x equals startfraction 55 over 4 endfraction . in which step did he use the addition property of equality? a table titled rahul's solution with 2 columns and 5 rows. the first column, steps, has the entries 1, 2, 3, 4. the second column, resulting equations, has the entries, 2 x minus startfraction 1 over 4 endfraction minus startfraction 3 over 5 endfraction x equals startfraction 55 over 4 endfraction, startfraction 7 over 5 endfraction x minus startfraction 1 over 4 endfraction equals startfraction 55 over 4 endfraction, startfraction 7 over 5 endfraction x equals startfraction 56 over 4 endfraction, x equals 10. step 1 step 2 step 3 step 4
Answers: 3
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The perimeter of a triangle is 69 cm. the first is 5 cm shorter than the second side. the third side is twice as long the first side. find the length of each side
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‼️‼️‼️‼️‼️the pressure exerted on the walls of a container by a gas enclosed within it is directly proportional to the temperature of the gas. if the pressure is 6 pounds per square inch when the temperature is 440 f, find the pressure exerted when the temperature of the gas is 380°f. (show work)
Answers: 1
Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus startfraction 1 over 8 endfraction ri...
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