An acute angle 0 is in a right triangle with cos 0=9/10. what is the value of sec 0

The value of sec O is  

Step-by-step explanation:

Given as for right angle triangle

cos O =

Now from Pythagoras theorem, for right angled triangle

H² = P² + B²

∵ cos O =  =

So Perpendicular² = Hypotenuse² - Base²

Or, Perpendicular² = 10² - 9²

Or, Perpendicular² = 100 - 81 = 19

∴   Perpendicular ( P ) =

∵ , Sec Ф =

So ,    Sec O =

Hence The value of sec O is      Answer

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25