Find the nth of each sequence a1 = 8,d = 3,n n = 16

16th term of the given sequence is 53.

Step-by-step explanation:

Here, the first term (a 1)  = 8

Common Difference (d)   = 3

n = 16

Now in ARITHMETIC PROGRESSION:

The nth term of any sequence is given as

⇒ a 16 is given as:

⇒  a (16) =  53

Hence, 16th term of the given sequence is 53.

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

i dont understand

step-by-step explanation: