Solve the following system of equations:

x + 3y = −4
x + 5y = −6

a) (1,1)
b) (-1,1)
c) (1,-1)
d) (-1,-1)

D) (-1,-1)

Step-by-step explanation:

Given that:

x + 3y = −4   eq1

x + 5y = −6 eq2

Subtracting eq1 from eq2 we get:

2y = -2

Dividing both sides by 2 we get:

y = -1

Put value of y in eq1

x + 3(-1) = -4

x - 3 = -4

x = -4 + 3

x = -1

so the solution set is (-1,-1)

i hope it will help you!

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: