If you can me, i will mark you brainliest. also earn 25 ! suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $ 45 . for one performance, 30 advance tickets and 20 same-day tickets were sold. the total amount paid for the tickets was $ 1150 . what was the price of each kind of ticket?

Advance ticket costs $25

Same-day ticket costs $20

Step-by-step explanation:

Let x = the price of one the advance ticket.

Let y = the price of one same-day ticket.

The combined cost of one advance ticket and one same-day ticket is $ 45. This means

x + y = 45 - - - - - - 1

For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means

30x + 20y = 1150 - - - - - - - - -2

From equation 1, x = 45- y

Put x = 45- y in equation 2

30( 45-y) + 20y = 1150

1350 - 30y + 20y = 1150

-10y = 1150-1350

-10y = -200

y = 200/10 = $20

x = 45-y

x =45-20= $25

Advance ticket costs $25

Same-day ticket costs $20

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²