Aline has a slope of 2 and passes through the point (1, 3). an equation of the line is a) y = x + 2 b) y = x + 1 c) y = 2x + 1 d) y = 3x - 2

The equation of line with given slope and points is y = 2 x + 1  

Step-by-step explanation:

Given as :

The slope of line is ( m ) = 2

The line passes through points ( 1 , 3 )

The equation of line is given as

y = m x + c

Now since slope of line is 2 and passing through points ( 1 , 3 )

∴ 3 = ( 2 )× ( 1 ) + c

Or, 3 - 2 = c

So c = 1

∴ The equation of line can be written as

y = 2 x + 1

Hence The equation of line with given slope and points is y = 2 x + 1  Answer

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation:

goog be able to you with that maybe