Write the point-slope form of the equation of the line through point (6, -2) that is perpendicular to the line y=2x-3

The point - slope form of the equation of line 1 is y = (-1/2)x + 1

Step-by-step explanation:

here, the given point on the equation  1  is A(6, -2).

Now, equation of line 2 is y = 2x - 3

Comparing it with the INTERCEPT SLOPE FORM :  y =  mx + C

Slope of Line 2    = 2  (= m2)

Now,as line 1 is perpendicular to line 1

⇒ Slope of line 1  x Slope of line 2  = -1

or, slope of line 1  = (-1/2)

Now, by POINT SLOPE form of a equation:

An equation with point (x0 , y0) and slope m is given as

(y - y0)=  m (x - x0)

Here, the equation of line 1 with point (6, -2) and slope (-1/2) is given as:

Hence, the point - slope form of the equation of line 1 is y = (-1/2)x + 1

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!