18)
draw a line segment of any length and label it po.
if you were to construct a line segment congruent to pq, what would be your first step?
a)
put one end of the compass on point p and the other end on point q.
measure pq using a ruler.
draw an arc the size of pq below the segment.
draw a new segent below the line the same length as po.

I'd say

Put one end of the compass on point P and the other end on point Q.

This way, you can construct (part of) a circumference with radius PQ with center P.

If you connect point P with any point on the circumference, this segment will be another radius of the circumference, and thus congruent to PQ.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50