find the least common multiple.

3x^3, 12y^2, and 15xy^3

a. 30x^4y^5

b. 60x^4y^5

c. 60x^3y^3

d. 540x^3y^3

C

Step-by-step explanation:

When we speak about the least common multiple, we are talking about the lowest number in which these given values are a factor of

Firstly, I would like to consider the number parts only I.e 3, 12 and 15. Using the long division l.c.m method, the lowest common multiple of these is 60.

In the options, there are two options carrying 60. How do we know which is correct? We simply look at the alphabets and try the long division again.

The highest powers of x and y is the 3rd power and hence gives their lowest common multiple.

Please check the attachment for the long division.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a