In the braces be low , list all the subsets of the set {7,6}

The subsets are

{7,6}

{7}

{6}

{ }

There are four subsets

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Explanation:

A subset is simply a set that contains one or more members of the original set. So all we do is list various ways to pick items from {7,6}. We could pick both items and simply write down the original set itself. Any set is a subset of itself.

Or we could pick one value from the set and have {7} or {6}. These sets are called singletons, as they contain one single value.

Finally, we could have a set with nothing inside it. We write this as { } which is a pair of curly braces with space between them to indicate "empty set". A special symbol for the empty set is

Note how the original set has n = 2 members. The rule is that there will be 2^n = 2^2 = 4 subsets. If the original set had say n = 3 members, then there would be 2^n = 2^3 = 8 different subsets. And so on. The collection of all the subsets possible is called a power set.

здрасти

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2