Blm and np if l(-2, 2) m(2,5) and n(0,2) p(3,-2)
are they parallel, perpendicular, or neither?

Perpendicular to each other.

Step-by-step explanation:

slope of LM (m1)

=(5-2) / [2-(-2)]

=3/4

slope of NP (m2)

=(-2-2) / (3-0)

=-4/3

For LM and NP to be parallel, their slopes must be equal ,

But m1≠ m2

For LM and NP to be perpendicular, their product of slopes must be equal to -1,

m1 × m2

= (3/4) ×(-4/3)

= -1

89

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.