Mrs. sprinkles surveyed her algebra classes about if they prefer dogs or cats. the students who prefer dogs represent 5 less than 2 times the number of students who prefer cats. if 62 students were surveyed, how many students prefer dogs?

43 students prefer dogs.

SOLUTION:

Given, Mrs. Sprinkles surveyed her Algebra classes about if they prefer dogs or cats. The students who prefer dogs represent 5 less than 2 times the number of students who prefer cats. If 62 students were surveyed, we have to find number of students prefer dogs.

Now, let the number of students who like cats be n, then number of students who like dogs will be .

So, now, according to given information, Students who like dogs are 5 less than twice that of those who like cats

Here, number of students can’t be in fractions, Now, let us see a condition where students who like dogs are 5 more than twice the students who prefers cats.

Then,

This is a possible condition. So,19 students like cats, then students like dogs.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.