25 points! a hot bowl of soup cools according to newton's law of cooling. its temperature, t, (in degrees fahrenheit) at a time, t, is given by t(t)=66+131e^-0.05t, where t is given in minutes.

what should you plug in for time, t, to find the initial temperature, t, of the soup?

what's the initial temperature?

what was the temperature of the soup after 15 minutes?

how long after serving is the soup 120°f?

answer: no idea

step-by-step explanation: i just want points

idk wbu

step-by-step explanation:

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.