The probabilty that husband and wife will be a live is 30 years from now is 0.6 and 8.0 find the probabilty that in 30 years time a) both will be a live b) nether will be die c) at least one will be a live

a) 0.48

b) 0.08

c) 0.44

Step-by-step explanation:

The probabilty that husband and wife will be a live 30 years from now is 0.6 and 8.0.

If probability that husband will be alive 30 years from now is 0.6, then the probability that husband will not be alive 30 years from now is

1 - 0.6 = 0.4

If probability that wife will be alive 30 years from now is 0.8, then the probability that wife will not be alive 30 years from now is

1-0.8 = 0.2

a) probability that both will be a live will be

0.6 × 0.8 = 0.48

b) probability that nether will be alive

is

0.4 × 0.2=0.08

c) probability that at least one will be alive will be

Probability that husband would be alive and wife would die + probability that husband would die and wife would be alive

= 0.6×0.2 + 0.4 ×0.8

= 0.12+ 0.32 = 0.44

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.