What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

The nth term of the series is

Step-by-step explanation:

Given: Third term = 24 and r = 6

We are given third term and common ratio of geometric series.

Formula:

For third term, n=3 and r=6

We need to find nth term of the series

Hence, The nth term of the series is

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Step-by-step explanation:

2/3 * 6^(n-1)

Step-by-step explanation:

The formula is a*r^(n-1)

so if the 3rd term (n=3) is 24 and the common ratio, r, is 6

24 = a* 6^(3-1)

So we are looking for a, yeah. 3-1 is 2 so 6^2 is 36. Simplify

24/36 = a

2/3 = a

Then just use that to write formula of the sequence

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step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180