the position-time graph of an object is shown below. what is the velocity of the object when time t = 2.5 seconds

2 m/s

Step-by-step explanation:

The position time graph shown above has position or distance on the vertical axis and time on the horizontal axis. The unit of the distance is in metes and the unit of the time is in seconds.

Distance = velocity / time

Time = distance × time

From the graph, the slope at any point determines the velocity of the object at that point.

Slope =( y2 -y1)/ ( x2 -x1)

y2 = 5(corresponding to the point on the vertical axis where t = 2.5 on the horizontal meets the plotted line when traced along the vertical axis)

y 1 = 0 (initial distance)

x2 = 2.5( on the horizontal axis)

x1 = 0(initial time)

Velocity = slope = (5-0)/2.5-0)= 5/2.5

= 2 m/s

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2