10. a bacteria is growing continually at a rate of 2.34% per hour. if the bacteria is first found
to be 850mg, in how many hours will it take to reach 1000mg?

The time to reach 1000 mg is 7 hours

Step-by-step explanation:

Given as :

The rate at which bacteria growing = 2.34% per hour

The initial amount of bacteria = 850 mg

The final amount of bacteria   = 1000 mg

Let The time period fro bacteria growing = T hours

Now, Final value = Initial value ×

Or,    1000 mg     = 850 mg ×

Or,     =

Or,    1.1764                                 =  

Or,    1.1764                                 =

Or,    Taking log both side

       log(1.1764) = log ( )

Or,  0.07055 = T × 0.01004                                   ( )

∴   T = 7.026  hour or T ≈ 7  hours

Hence The time to reach 1000 mg is 7 hours  Answer

an altitude of 15,000 feet

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.