Atotal of 192 units is planned, and the number of family units (2 and 3 bedroom townhouses) will equal to the number of 1 bedroom units. if the number of 1 bedroom units will be 3 times the number of 3 bedroom units, find how many units of each type will be in the complex.

96 one bedroom homes

64 two bedroom homes

32 three bedroom homes

Step-by-step explanation:

If x is the number of 1 bedroom homes, y is the number of 2 bedroom homes, and z is the number of 3 bedroom homes:

x + y + z = 192

x = y + z

x = 3z

Solve the system of equations using substitution or elimination.  Using substitution:

x + x = 192

2x = 192

x = 96

z = x / 3

z = 32

y = x − z

y = 64

i'm sure goog can you get that answer