Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expansion of (2+x-x^2)^6
answer quickly

The first 3 terms in the expansion of , in ascending power of x are,

coefficient of in the expansion of = (240 - 192) = 48

Step-by-step explanation:

=

= + terms involving higher powers of x

= + terms involving higher powers of x

so, the first 3 terms in the expansion of , in ascending power of x are,

Again,

=

Now, by inspection,

the term comes from k =5 and k = 6

for k = 5, the coefficient of    is , = -192

for k = 6 , the coefficient of is, = 240

so,   coefficient of in the final expression = (240 - 192) = 48

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step-by-step explanation:

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: