Aball is thrown in the air from the top of a building. its height, in meters above ground, as a function of time, in seconds, is given by h(t)=−4.9x2+19.6x+24.how long does does it take for the ball to reach its maximum height? what is the maximum height of the ball? (round your answer to three decimal places)

It would take 2 second to reach its maximum height.

The maximum height of the ball is 43.6 meters above the ground.

Step-by-step explanation:

Consider the provided function.

The above function's graph is a downward parabola and the maximum of the downward parabola is at its vertex.

We can find the x coordinate of the function using the formula:

Substitute a=-4.9 and b=19.6 in

Hence, it would take 2 second to reach its maximum height.

Substitute x=2 in above formula.

Hence, the maximum height of the ball is 43.6 meters above the ground.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465