In triangle δabc, ∠c is a right angle and cd is the height to
ab. find the angles in δcbd and δcad if:

m∠a = α

m∠cdb =

m∠cbd =

m∠bcd =

m∠cda =

m∠cad=

m∠acd =

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

From ΔCBD,

is same as .

So,

Now, from ΔCAD,

is same as

So,

Hence, the unknown angles of both the triangles are:

mx+89b(-98)nb

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.