Astudent on a piano stool rotates freely with an angular speed of 2.85 rev/s . the student holds a 1.50 kg mass in each outstretched arm, 0.789 m from the axis of rotation. the combined moment of inertia of the student and the stool, ignoring the two masses, is 5.53 kg⋅m2 , a value that remains constant. as the student pulls his arms inward, his angular speed increases to 3.60 rev/s . how far are the masses from the axis of rotation at this time, considering the masses to be points

r'=0.327 m

Step-by-step explanation:

Given

angular velocity

mass of objects

distance of objects from stool

Combined moment of inertia of stool and student

Now student pull off his hands so as to increase its speed to 3.60 rev/s

Initial moment of inertia of two masses

After Pulling off hands so that r' is the distance of masses from stool

Conserving angular momentum

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

i would pic false cause it goes down towards negative

step-by-step explanation: