In this question, f : r -r is a differentiable function. we will use linear ra try to find a good linear approximation to f near a point x=a. our linear approximation will be of the form y = c+ma. use the values of f at the point x = a and the nearby point x = a + h to find a good approximation. (you will need to set up a linear system involving c, m, a, h, f(a), f(a + h), where c and m are the variables. you should also be able to solve this linear system exactly for the vector c m .)

could you reply to this with the question so i can ?

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.