(1 point) the soot produced by a garbage incinerator spreads out in a circular pattern. the depth, h(r), in millimeters, of the soot deposited each month at a distance r kilometers from the incinerator is given by h(r)=0.114e−1.8r. (a) write a definite integral (with independent variable r) giving the total volume of soot deposited within 5 kilometers of the incinerator each month. volume = ∫50 (include units) (b) evaluate the integral you found in part (a) to find the volume of soot.

a)

b)

Step-by-step explanation:

We have that the depth, in millimeters, of the soot deposited each month at a distance r kilometers from the incinerator is given by:

(a) Write a definite integral (with independent variable r) giving the total volume of soot deposited within 5 kilometers of the incinerator each month.

This is the integral of H(r) with r varying from 0 to 5. So:

(b) Evaluate the integral you found in part (a) to find the volume of soot.

5

step-by-step explanation:

the answer is b.

surface area: 169π

volume: 366π

i got it down.