In the year 2005 , a total of 750 fish were introduced into a manmade lake . the fish population was expected to grow at a rate of 8.3% every year .

what will the fish population be in 2050 ?
round to the nearest whole number . hurry

The fish population will be in 2050 = 27,123

Step-by-step explanation:

Given,

In 2005, the total number of fish were introduced (fish population), PV = 750

The growth rate, i = 8.3% = 0.083

The difference between 2050 and 2005 is (2050 - 2005), n = 45 years

We need to solve this problem with the help of future value of compounding. We know, FV = PV (1+i)^n, where, PV = present value, i = interest rate, n = period.

Therefore, the fish population will be in 2050 = 750 x (1 + 0.083)^45

The fish population will be in 2050 = 27,123.26

2050 fish population = 27,123 (Nearest to whole number).

27,123.26 which you round down to 27,123

Step-by-step explanation:

I took the test and got it right.

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: