Anet force of 100 newton's is applied to a 20-kilogram cart that is already moving at 3 meters per second. the final speed of the cart was 8 meters per second. for how long was the force applied?

The Force is applied for 1 sec

Step-by-step explanation:

Given as :

The Total force applied on cart = 100 Newton

The mass of cart                         = 20 kg

The initial velocity of  cart ( v1)   = 3 meter per second

The final velocity of cart (v2)      = 8 meter per second

∵ Force = mass × acceleration

Or, 100 N = 20 kg × acceleration

Or,  Acceleration =

Or,  Acceleration = 5 Newton per kg

Again ∵   Acceleration = Rate of change of velocity

I.e           Acceleration =

Or,           5 Newton per kg =  

Or,           Time     =   = 1 sec

Hence The Force is applied for 1 sec   Answer

0.6

39mph

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!