When fishing off the shores of florida, a spotted seatrout must be between 24 and 30 inches long before it can be kept; otherwise, it must be returned to the waters. in a region of the gulf of mexico, the lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches. what is the probability that a fisherman catches a spotted seatrout within the legal limits?

 0.2858

Step-by-step explanation:

Given : When fishing off the shores of Florida, a spotted seatrout must be between 24 and 30 inches long before it can be kept.

In a region of the Gulf of Mexico, the lengths of the spotted seatrout that are caught, are normally distributed with and .

Let x be the lengths of the spotted seatrout that are caught .

Using formula

For x= 24

For x= 30

Then, by using the z-value table , the probability that a fisherman catches a spotted seatrout within the legal limits will be :-

Hence, the probability that a fisherman catches a spotted seatrout within the legal limits = 0.2858

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

360/29

step-by-step explanation: