According to a 2008 study published by the afl-cio, 78% of union workers had jobs with employer health coverage compared to 51% of nonunion workers. in 2009, the employee benefit research institute cited data from large samples that suggested that 80% of union workers had health coverage compared to 56% of nonunion workers. let’s suppose the 2009 data came from random samples of 3,000 union workers and 5,000 nonunion workers. compute the mean of the sampling distribution of differences in the proportions insured.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

their is no graph showing

step-by-step explanation:

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step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.