Ihave a deck of $54$ cards, and i deal all of the cards to $x$ players, with each player getting $y$ cards. if $x$ is at least $2$ and $y$ is at least $5$, then how many possible values of $x$ are there?

4

Step-by-step explanation:

We want xy=54=2*3^3 such that x is at least 2 and y is at least 5. Thus, the possible combinations (x,y) are (2,27), (3,18), (6,9), and (9,6). There are 4 such combinations.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.