Suppose that a recent poll of american households about car ownership found that for households with a car, 39% owned a sedan, 33% owned a van, and 7% owned a sports car. suppose that three households are selected randomly and with replacement. what is the probability that all three randomly selected households own a van? (round to the nearest thousandth) select one: a. 0.036 b. 0.059 c. 0.003 d. 0.964

Option 'a' is correct.

Step-by-step explanation:

Since we have given that

Probability of owned a sedan = 39%

Probability of owned a van = 33%

Probability of owned a sports car = 7%

n = 3

We need to find the probability that all three randomly selected households own a van.

So, Probability of getting all 3 own a van is given by

Hence, Option 'a' is correct.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option