Adepartment store accepts either the american express card or the visa credit card. a total of 24% of its customers carry an american express card, 61% carry a visa card, and 11% carry both cards. what is the probability that a customer of this department store carries a credit card that the store will accept (either american express or visa)?

0.74

Step-by-step explanation:

Data provided :

Customers carrying an American express card, P(A) = 24%

customers carrying a VISA card, P(V) = 61%

Customers carrying both the cards, P(A∩V) = 11%

Now,

probability that a customer of this department store carries a credit card that the store will accept i.e

Probability that the customer is carrying either  American Express or VISA

P(A∪V) = P(A) + P(V) - P(A∩V)

or

P(A∪V) = 24% + 61% - 11%

or

P(A∪V) = 85% - 11%

or

P(A∪V) = 74% = 0.74

m∠vru = 80°

m∠urw = 15°

step-by-step explanation:

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8