Rolle's theorem cannot be applied to the function f(x) = x1/3 on the interval [-1, 1] because

Answer with Step-by-step explanation:

We are given that a function

on the interval [-1,1]

Rolle's theorem : It states that function is continuous on close interval [a,b] and differentiable on open interval (a,b) such that f(a)=f(b) , then

for some x

f is not differentiable at x=0.Therefore , f(x) is not diffrentiable on interval (-1,1)

Hence, Rolle's threorem cannot be applied for given function because it does not satisfied the condition of rolle's theorem.

6.5

step-by-step explanation:

you said it was in the question

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