Given p(a)= 0.4 and p(b) = 0.3 , if a and b are mutually exclusive events compute p(aorb)

For mutually exclusive events,  P(A or B)    = 0.7

Step-by-step explanation:

P(A) = 0.4

P(B) = 0.3

Here, A and B are mutually exclusive events.

⇒ A  ∩  B = Ф

    P(A  ∩  B) = 0

So, P(A or B)  = P(A) + P(B) - P(A ∩B)

=  0.4 + 0.3  - 0

= 0.7

⇒ P(A or B)  = 0.7

Hence, for mutually exclusive events,  P(A or B)    = 0.7

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

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step-by-step explanation: