1.) a projectile launched straight up into the air with an initial velocity of 20 meters per second from a height of 10 meters. how long will it take for the projectile to hit the ground?
a.) which formula should be used?
h(t) = -4.9t² + vot + ho
h(t) = -16t² + vot + ho
b.) what is the vo?
c.) what is the ho?
d.) use the quadratic formula to solve

Hello,

I have just answered the question

gravity on earth :g=9.81 m/s²


9.81/2≈4.9



Answer 1

2)
h(t)=-4.9*t²+20*t+10

To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²

t=(-20-4√35)/(-4.9*2)=4,4555...(s)

t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )