What is the number of possible outcomes if three quarters are tossed and the total numbers of heads and tails are counted? a) 2 b) 4 c) 6 d) 8

D). 8.

Step-by-step explanation:

Each quarter will come up heads or tails  - that is 2 possibilities.

So for  3 tosses the number of outcomes is 2*2*2 = 8.

Their are 8 outcomes

Step-by-step explanation:

The amount of quarters = 3

The sides on the quarters = 2

2^3 = 8

answer: options?

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.