Consider the following switch statement where x is an int. if x is currently equal to 5, what will the value of x be after the switch statement executes? switch (x) { case 3 : x += 1; case 4 : x += 2; case 5 : x += 3; case 6 : x++; case 7 : x += 2; case 8 : x--; case 9 : x++

x=11

Step-by-step explanation:

The switch case works like an if or if-else, where each of the cases are conditionals. Here we have 7 cases and we know that our variable begins with x=5.

First, it enters to case 5 because of x=5, so x+=3, this means we add 3 to the actual value of the variable ⇒ x=8.  

At this point, if there's not break the program continues to the next case, executing the statements until a break or the end on the switch is reached.  

In this order, the x = 8 and next we add 1 (case 6) ⇒ x=9. We add 2 (case 7) x+=2 ⇒ x=10. Then we rest 1 (case 8) ⇒ x=9 and then we add 1 again as in case 9 ⇒ x=11.

d i think

step-by-step explanation:

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5