The shed is filled with sawdust whose density (mass/unit volume) at any point is inversely proportional to the distance of that point from the floor. that is, if the constant of proportionality is k, and y is the distance from the bottom of the shed, the density of the sawdust in the shed at height y is given by ky. find a, b, and f(y) so that the mass of the sawdust in the shed is given by ∫baf(y) dy.

$12. that is my answer.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

a

step-by-step explanation:

the answer is a