The associated press (october 9, 2002) reported that in a survey of 4722 american youngsters aged 6–19, 15% were seriously overweight (a body mass index of at least 30; this index is a measure of weight relative to height). calculate and inter- pret a confidence interval using a 99% confidence level for the proportion of all american youngsters who are seriously overweight.

We are 99% sure that the proportion of all American youngsters who are seriously overweight is between 0.1366 and 0.1634.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

Z is the zscore that has a pvalue of .

For this problem, we have that:

In a survey of 4722 American youngsters aged 6–19, 15% were seriously overweight, so .

Calculate and inter- pret a confidence interval using a 99% confidence level for the proportion of all American youngsters who are seriously overweight.

So , z is the value of Z that has a pvalue of , so Z = 2.575.

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence level for the proportion of all American youngsters who are seriously overweight is (0.1366, 0.1634).

We are 99% sure that the proportion of all American youngsters who are seriously overweight is between 0.1366 and 0.1634.

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.