According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.157. the probability that a randomly selected person has vision problems is 0.096. can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? why or why not?

According to a center for disease control. We can’t compute the probability.

SOLUTION:

Given that, According to a center for disease control,  

The probability that a randomly selected person has hearing problems is 0.157.  

The probability that a randomly selected person has vision problems is 0.096.  

We have to find whether we can compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities or not?  

The answer is no, because hearing and vision problems are not mutually exclusive.

So, some people have both hearing and vision problems.

These people would be included twice in the probability.

Hence, we can’t compute the probability.

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.