Focus groups of 15 people are randomly selected to discuss products of the yummy company. it is determined that the mean number (per group) who recognize the yummy brand name is 12.5, and the standard deviation is 0.58. would it be unusual to randomly select 15 people and find that fewer than 9 recognize the yummy brand name?

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

Step-by-step explanation:

Consider the provided information.

The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.

Mean = μ= 12.5  

σ = 0.58

n = 15

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18