The equation of line p is y = ax + b. which of these could be the equation of line q?

a. y=-2a(x+3)+b
b. y=-2ax+b
c. y=-2ax+b+3
d. y=-2ax+b-3

Line q is decreasing (negative slope), whereas line p is increasing (positive slope). Moreover, the absolute value of the slope of line q is higher that the one of line p, because line q is more "vertical" than line p.

Finally, line p passes through the origin (b=0), whereas line q has a y-intercept of 3 (constant term=3).

So, the most feasible expression for line q would be y=-2ax+b+3

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get