The temperature of dry ice is -109.3. this is 184.9 less than the outside temperature. write and solve an equation to find the outside temperature t.

75.6 units

Step-by-step explanation:

The dry ice has a temperature of -109.3 units.

The outside temperature is 184.9 units more than the dry ice temperature.

If the outside temperature is C then we can write from the above condition as  

C - 184.9 = - 109.3 ...this equation gives the temperature of outside.

Solving it we get C = 184.9 - 109.3 = 75.6.

So the outside temperature is 75.6 units. (Answer)

x^2 + 10x + 38 + 161/x-4

to find this, you'll need to synthetically divide using synthetic division.

here's how you would set it up:

4 is what you're dividing by (set x -4 = 0)

the numbers you are 'dividing' by are 1, 6, -2, and 9 or the coefficients of the terms listed above.

bring the first term down (1), multiply that by 4 before raising it to the next term to add (6). repeat this process as so:

6 + 4 = 10; 10 x 4 = 40; 40 - 2 = 38 x 4 = 152 + 9 = 161

161 is over x-4 as there are now two constants and you cannot combine them.

also, i'm not sure if it was -9 or +9, so i assumed.

hope this !