given p(a) = 0.072, p(b) = 0.180, and p(c) = 0.027, and that events a, b, and c are mutually exclusive, what is the p(a or b or c)?

Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279

Solution:

Given that probability of event A is P(A) = 0.072

Probability of event B is P(B) = 0.180

Probability of event C is P(C) = 0.027

Also event A, B and C are mutually exclusive.

Need to determine P( A or B or C )

For mutually exclusive events  

P( A or B or C ) = P(A) + P(B) + P(C)

= 0.072 + 0.180 + 0.027  = 0.279

Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.

were is the equation

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

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