If someone could work out the first half of the problem and explain that would be great!

x = -5

y = -5

Step-by-step explanation:

If you multiply the top equation by negative 2, you can add it to the bottom equation and cancel out the x:

-2(-x + 5y = -20) --> 2x - 10y = 40

Add this to the bottom equation top to bottom:

2x - 10y = 40

-2x + 4y = -10

You get:

-6y = 30

Then solve for y:

y = -5

Plug this back in for either equation and solve for x:

-x + 5(-5) = -20

-x -25 = -20

-x = 5

x = -5

Your answers are:

x = -5

y = -5

x =-5

y = -5

Step-by-step explanation:

-x + 5y = -20 1

-2x + 4y = -10 2

Multiply eqn 1 by 2 and eqn 2 by 1

This is done to make coefficients of x in both equations the same so that x can be eliminated

-2x + 10y = -40

-2x + 4y = -10

Subtracting

6y = -30

y = -5

Substitute y = -5 in eqn 1

-x+5×-5=-20

-x - 25= -20

-x = -20+25 = 5

x = -5

been looking for the answer havent been able to find it   but good luck with it

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1