Given: ab ii de, ac = ce
prove: a abc = a edc

Step-by-step explanation:

Here  given:   AB II DE, AC = CE

Now, in ΔABC and ΔEDC

As,  AB II DE (given)

⇒∠BAC = ∠CED   (Alternative pairs of angles)

and  ∠ABC = ∠CDE  (Alternative pairs of angles)

and AC = CE (given)

So, by the congruent  property of AAS

(ANGLE ANGLE SIDE) which states that two triangle are congruent if two angles and one side of one triangle is equal to the two angles and one side of the other triangle.

                                ΔABC ≅  ΔEDC

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