Charlie is watching hot air balloons. balloon a has risen at a 56° angle. balloon b has risen at an 81° angle. if the distance from balloon a to the ground is 1,200 feet, how far is balloon b from balloon a? round your answer to the nearest whole number.

Balloon B is 3910 feet above balloon A.

Step-by-step explanation:

The figure for the given scenario is shown below.

From the figure,

QR is the distance of balloon A or B from Charlie, SR is the distance of balloon A from ground, is the angle of elevation of balloon A, is the angle of elevation of balloon B. S is the position of balloon A and P is the position of balloon B.

So, as per the question,

SR = 1200 ft, °, °.

From triangle ΔSQR,

Now, consider triangle ΔPQR.

Now, difference in the height of balloon A and B is given by the segment PS.

So,

Therefore, the balloon B is 3910 feet above balloon A.

The correct answer is 999 feet.

Step-by-step explanation:

Because you have to find the distance between them you have to use the tan method. ( tan<=opp/adj ) For ballon A :

tan56=1,200/x

tan56 ( 1.482560969)

( 1.482560969 )/ 1,200

x= 809 feet

For Ballon B:

tan81=1200/x

tan81 ( 6.313751515 )

( 6.313751515 )/ 1,200

x=190

It's then asking the distance from ballon a to ballon b so you then add the distances together ( 809 + 190 ) which is then equivalent to 990. I hope this really helps you out if it did and i hope im not late pls mark brainliest thx!

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: