An arithmetic progression is a sequence of numbers in which the distance (or difference) between any two successive numbers if the same. this in the sequence 1, 3, 5, 7, the distance is 2 while in the sequence 6, 12, 18, 24, the distance is 6. given the positive integer distance and the integers m and n, create a list consisting of the arithmetic progression between (and including) m and n with a distance of distance (if m > n, the list should be empty.) for example, if distance is 2, m is 5, and n is 12, the list would be [5, 7, 9, 11]. associate the list with the variable arith_prog.

[m, m+d, m+2d, - - - - -, n]

Step-by-step explanation:

We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d

Where a_(n) is the nth term of the sequence

a_(1) is the first term of the sequence

n is the number of the term like if we are talking about 7th term so the n is 7.

d is the difference between two successive terms.

For this problem we know our first term that is m, our last term that is n and our difference that is d.

For second term we will use the formula

a_(2) = m + (2-1)d

a_(2) = m + (1)d

a_(2) = m + d

Similarly,

a_(3) = m + (3-1)d

a_(3) = m + (2)d

a_(3) = m + 2d

i believe the correct answer is b.